| 品牌 : | 春晨 | 型号 : | JFEM |
| 线芯材质 : | 镀锡铜线 | 芯数 : | 1 |
| 电线 外径 : | 100 | 护套厚度 : | 1.2 |
| 标称截面 : | 120 | 物料编号 : | 123 |
| 长度 : | 1000 | 加工定制 : | 是 |
| 温度范围 : | 90 | 小弯曲半径 : | 12 |
| 线径密度 : | 15 | 牵引段裂张力 : | 10 |
江苏春晨电缆有限公司生产JFEM1144电机引接线，
在施工组织设计的土建部分中，确定了各单元工程的施工方案，选择了所需要的机械设备，安排了施工进度，就可以对临时用电量的估算。
In the civil construction part of construction organization design, the construction scheme of each unit project is determined, the required mechanical equipment is selected, and the construction schedule is arranged, so that the estimation of the temporary electricity consumption can be made.
一种估算方法是同时考虑施工现场的动力和照明用电，可按照下列公式计算：
One estimation method is to consider both the power and lighting power consumption at the construction site. It can be calculated according to the following formulas:
S=K{（∑P1÷ηcosφ）K1K2+∑P2K3}
S=K{(P1_cos_) K1K2+P2K3}
公式中各部分的代表含义如下：
The representative meanings of each part of the formula are as follows:
S：工地总用电量；
S: Total site electricity consumption;
K：备用系数，一般取K=1.05~1.1；
K: Standby coefficient, generally K = 1.05 ~ 1.1;
∑P1：全工地动力设备的额定输出功率总和，KW；JFEM1144电机引接线
_P1: The total rated output power of power equipment in the whole site, KW;
∑P2：全工地照明用电量总和，KW；
_P2: The total lighting power consumption of the whole site, KW;
η：动力设备效率，即各电动机的平均效率，一般取η=0.85；
_: Power equipment efficiency, that is, the average efficiency of each motor, generally take_ = 0.85;;;;
cosφ：功率因素，建筑工地一般取用 0.65；
Cos_: power factor, construction site generally used 0.65;
K1：全部动力设备同时使用系数，一般五台一下时取K1=0.6，五台以上时取K1=0.4~0.5；
K1: The coefficients of simultaneous use of all power equipments are generally K1 = 0.6 at one time for five units and K1 = 0.4 ~ 0.5 at more than five units.
K2：动力负荷系数，主要考虑没有因性质不同在负荷时的工作情况，一般取K2=0.75~1；
K2: Power load factor, mainly considering the working conditions of different loads, generally take K2 = 0.75 ~ 1;
K3：照明设备同时使用系数，一般取K3=0.6~0.9；
K3: Lighting equipment coefficients at the same time, generally take K3 = 0.6 ~ 0.9;
另一种方法，如果工地照明用电量很小，为简明计算，可在动力用电量之外再加10%，作为总用电量，这就可以用下面的公式计算：
Another method, if the site lighting power consumption is very small, for concise calculation, it can be added 10% to the power consumption as the total power consumption, which can be calculated by the following formula:
S动=K1（∑P1÷ηcosφ）K2
S motion = K1 (P1_cos phi) K2
得出总的用电量之后，再计算工地所需的总电流，其公式为：
After the total electricity consumption is obtained, the total current required for the site is calculated. The formula is as follows:
I=（Sz×1000）÷（1.73×U）
I=(Sz*1000)(1.73*U)
公式中I：表示总电流，A；Sz：表示工地总用电量，KVA；U：表示供电系统的线电压，U=380V。
Formula I: Total current, A; Sz: Total site power consumption, KVA; U: Line voltage of power supply system, U = 380V.
